Calculation method of switching power supply for LED display screen

Feb 28, 2025

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Calculation method of switching power supply for LED display screen

 

Question 1: Power of PH10 and PH12.5 semi outdoor unit boards: If the number of LED points (lights) of the two models is the same, their power is theoretically the same, but the size of the 12.5 unit board is larger than that of the PH10 unit board!


Power calculation method: 0.02A (current) * 5V (voltage) * 32 * 16 (number of LED lights) * 1/4 (number of scans)=12.8W (unit board power)


Question 2: 12 P12.5 red semi outdoor unit boards require a 5V40A switching power supply, and 12 32 * 16 point PH12.5 unit boards have a power of 153.6W. A 5V40A200W switching power supply can meet the needs of 12 PH12.5 semi outdoor unit boards working!


LED display switch power supply with a set of wires and several boards
A typical 200W power supply can carry 16-20 boards. If it only comes with modules, it can be carried this way. However, if it comes with a system card, you don't need to carry so many boards. You need to leave some margin for the system card because it doesn't require much current, but has higher voltage requirements. It is recommended that those with system cards carry up to 14 fast modules. Of course, under normal operation of your display screen, the greater the voltage drop of the power supply with more modules, the shorter the service life of your power supply. If you calculate a module with a single lamp of 20mA, it will be 32 * 16 * 0.02/8=1.28A, plus the 0.5 consumed by the board itself, which is 1.78A. You can only use 85% of the rated power supply, which is 170W divided by 5V equals 36A divided by 1.78, approximately equivalent to 20 fast modules. This is the ideal maximum value. Generally, carrying 16 pieces is enough. Your 1.5mm ² wire can only carry a maximum of 12A, which means that you can carry a maximum of 6 pieces per set of wires. You can also use a 2.5mm ² wire to pass 22A. You can calculate it yourself. Although the current runs quickly, you also need to follow the principle of equal distribution, starting from the past and then going further. Your power cord should not be too long, or there may be voltage drops or brighter wires near the power source, and darker wires far away. You can take another look at the actual situation.

 

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